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132x=180+24x^2
We move all terms to the left:
132x-(180+24x^2)=0
We get rid of parentheses
-24x^2+132x-180=0
a = -24; b = 132; c = -180;
Δ = b2-4ac
Δ = 1322-4·(-24)·(-180)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-12}{2*-24}=\frac{-144}{-48} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+12}{2*-24}=\frac{-120}{-48} =2+1/2 $
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